A point B on a rigid link AB moves with respect to A with angular velocity $$\omega $$ rad/s. The total acceleration of B with respect to A will be equal to

A Vector sum of radial component and Coriolis component
B Vector sum of tangential component and Coriolis component
C Vector sum of radial component and tangential component
D Vector difference of radial component and tangential component

Correct Answer: Vector sum of radial component and tangential component

Bissoy MCQ
#Mechanical Engineering #Theory of Machine

Related Questions

A point B on a rigid link AB moves with respect to A with angular velocity $$\omega $$ rad/s. The radial component of the acceleration of B with respect to A, is (where vBA = Linear velocity of B with respect to A)
A vBA × AB
B $$\frac{{{\text{vBA}}}}{{{\text{AB}}}}$$
C v2BA
D $$\frac{{{{\text{v}}^2}{\text{BA}}}}{{{\text{AB}}}}$$
A disc is a spinning with an angular velocity $$\omega $$ rad/s about the axis of spin. The couple applied to the disc causing precession will be (where $$I$$ = Mass moment of inertia of the disc and $$\omega {\text{P}}$$  = Angular velocity of precession of the axis of spin)
A $$\frac{1}{2}I{\omega ^2}$$
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A slider moves at a velocity $${\text{v}}$$ on a link revolving at $$\omega $$ rad/s. The coriolis component of acceleration is
A $$\omega {\text{v}}$$
B $$2\omega {\text{v}}$$
C $${\omega ^2}{\text{v}}$$
D $$2\omega {{\text{v}}^2}$$
When a point at the end of a link moves with constant angular velocity, its acceleration will have
A radial component only
B tangential component only
C coriolis component only
D radial and tangential components both
2.4 omega এবং 3.8 omega তিনটি রোধক 54 V ব্যাটারির সাথে সিরিজ সংযোগ করা আছে। ব্যাটারি অভ্যন্তরীণ রোধ না থাকলে 3.6 omega রোধকের দুই প্রান্তে বিভব পার্থক্য কত?
A 6V
B 12 V
C 20 V
D 24 V
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A parallel to the link joining the points
B perpendicular to the link joining the points
C at 450 to the link joining the points
D none of the mentioned
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A $$\omega {\text{r}}\left( {\sin \theta + \frac{{\sin 2\theta }}{{\text{n}}}} \right)$$
B $$\omega {\text{r}}\left( {\cos\theta + \frac{{\cos2\theta }}{{\text{n}}}} \right)$$
C $${\omega ^2}{\text{r}}\left( {\sin \theta + \frac{{\sin 2\theta }}{{\text{n}}}} \right)$$
D $${\omega ^2}{\text{r}}\left( {\cos\theta + \frac{{\cos2\theta }}{{\text{n}}}} \right)$$
The velocity of the reciprocating roller follower when it has contact with the straight flanks of the tangent cam, is given by (where $$\omega $$ = Angular velocity of the cam shaft)
A $$\omega \left( {{{\text{r}}_1}{{\text{r}}_2}} \right)\sin \theta $$
B $$\omega \left( {{{\text{r}}_1} + {{\text{r}}_2}} \right)\sin \theta \sec 2\theta $$
C $$\omega \left( {{{\text{r}}_1}{{\text{r}}_2}} \right)\cos \theta $$
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In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if $$\frac{\omega }{{\omega {\text{n}}}}$$ is
A Equal to 1
B Equal to 2
C Less than 2
D Greater than 2
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B perpendicular to AB
C along AB
D at 450

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