An odd-parity generator produces an odd-parity bit to go along with the data. The parity of the transmitted data is _____ An XOR gate can test each received word for parity rejecting words with _____ parity.

In AES, to make the s-box, we apply the transformation b’_i = b_i XOR b_(i+4) XOR b(i+5) XOR b_(i+6) XOR b_(i+7) XOR c_i What is c_i in this transformation?

A

c_i is the ith bit of byte c with value 0x63

B

c_i is the ith bit of byte c with value 0x25

C

c_i is the ith bit of byte c with value 0x8F

D

c_i is the ith bit of byte c with value 0x8A

In AES, to make the s-box, we apply the transformation – b’i = bi XOR b(i+4) XOR b(i+5) XOR b(i+6) XOR b(i+7) XOR ci What is ci in this transformation?

A

ci is the ith bit of byte c with value 0x63

B

ci is the ith bit of byte c with value 0x25

C

ci is the ith bit of byte c with value 0x8F

D

ci is the ith bit of byte c with value 0x8A

The XOR gates are ideal for testing parity because even-parity words produce a _____ output and odd-parity words produce a _____ output

A

low, high

B

high, low

C

odd, even

D

even, odd

E

None of the above

There are flowers in a basket which are to be distributed to five persons standing in a row. The second person received half of the number of flowers given to the first person, the third person received half of the number of flowers received to the second person; the fourth person received half of the number of flowers received to the third person and the fifth person received half of the number of flowers received to the fourth person. If the fifth person received only one flower and there is no flower remaining in the basket, how many flowers were their in the basket?

A

31

B

32

C

16

D

15

একটি XOR লজিক গেট নিম্নলিখিত কোন লজিক গেট/ গেটগুলোর সমবায়ে গঠিত হতে পারে? (An XOR logic gate can be constructed from the combination of which of the following logic gate/gates?)

A

OR gate

B

AND gate, OR gate, and NOT gate

C

AND gate and NOT gate

D

OR gate and NOT gate

Which of the following statements are true? i) practical application of XOR linked lists are in environments with limited space requirements, such as embedded devices. ii)xor lists are not suitable because most garbage collectors will fail to work properly with classes or structures that don’t contain literal pointers iii)in order to calculate the address of the next node you need to remember the address of the previous node iv)xor lists are much efficient than single, doubly linked lists and arrays

A

i, ii, iii, iv

B

i, ii, iii

C

i, ii

D

i

The inverse s-box permutation follows, b’_i = b_(i+2) XOR b(i+5) XOR b_(i+7) XOR d_i Here d_i is

A

d_i is the ith bit of a byte ‘d’ whose hex value is 0x15

B

d_i is the ith bit of a byte ‘d’ whose hex value is 0x05

C

d_i is the ith bit of a byte ‘d’ whose hex value is 0x25

D

d_i is the ith bit of a byte ‘d’ whose hex value is 0x51

The Chi function is defined as ← a XOR ( aXOR 1) AND a) b) a ← a AND ( aXOR 1) AND a) c) a ← a AND ( a XOR a) d) a ← a XOR ( a AND a)

A

a ← a XOR ( aXOR 1) AND a)

B

x

C

x

D

x

The inverse s-box permutation follows, b’i = b(i+2) XOR b(i+5) XOR b(i+7) XOR di Here di is –

A

di is the ith bit of a byte ‘d’ whose hex value is 0x15

B

di is the ith bit of a byte ‘d’ whose hex value is 0x05

C

di is the ith bit of a byte ‘d’ whose hex value is 0x25

D

di is the ith bit of a byte ‘d’ whose hex value is 0x51

In conducting an empirical study a researcher employs a non-parametric test for data analysis and finds that the ‘statistics’ arrived at is ‘significant’ at .05 level. What decisions will be warranted thereafter? (A) Rejecting the Null hypothesis (H0) (B) Accepting the Null hypothesis (H0) (C) Accepting the alternate hypothesis (H1) (D) Keeping the decision in abeyance (E) Rejecting the alternate hypothesis (H1) Choose the correct answer from the options given below :

A

(A) and (B) only

B

(B) and (C) only

C

(D) only

D

(A) and (C) only

An odd-parity generator produces an odd-parity bit to go along with the data. The parity of the transmitted data is _ An XOR gate can test each received word for parity rejecting words with _ parity.

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