Ten years ago, A was half of B in age. If the ratio of their present ages is 3 :4 then what will be the total of their present ages?
A
30 years
B
35 years
C
40 years
D
45 years
Correct Answer: 35 years
Let , Ten years ago, B was = x ∴ now = x + 10 and Ten years ago, A was = x2 ∴ now = x2 x + 202ATQ, x + 202x + 10 = 34⇒x + 202x + 20 = 34⇒6x + 60 = 4x + 80⇒6x - 4x = 80 - 60⇒2x = 20⇒x = 202.'.x = 10Present age of B,A = x + 10 and x + 202 = 10 + 10 and 10 + 202 = 20 and 15.'. sum = 20 + 15 = 35 years