When a ring of metal is heated what happens to its hole ?

A Expands
B Contracts
C It expands or contracts according to its diameter
D It expands or contracts according to its coefficient of expansion

Correct Answer: Expands

The hole size will increase because in expansion the size between two molecules do not increase so when the molecules on the outer edge move outward. Due to expansion, the size of the hole will also increase so as to compensate the distance change between the molecules.

Related Questions

A metal plate with a circular hole at the centre is heated. What will happen to the area of the hole ?
A plate with an elliptical hole in the centre, with semi-major axis (a) perpendicular to the direction of loading and semi-minor axis (b) along the direction of loading, is subjected to a pull P. The maximum stress induced at the edge of the hole is equal to (where $$\sigma $$ = Stress for a plate with no hole i.e. nominal stress)
When a hole of diameter ‘d’ is punched in a metal of thickness 't', then the force required to punch a hole is equal to (where $${\tau _{\text{u}}}$$ = Ultimate shear strength of the material of the plate)
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