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The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is = ?

The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is = ? Correct Answer 1683

LCM of 5, 6, 7, 8 = 840
∴ Required number is of the from 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2
∴ Required number
= (840 × 2 + 3)
= 1683

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