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If the ∠ABC and ∠ACB of triangle ABC is 80 deg and 60 deg respectively. If the Incenter of the triangle is at point I then calculate angle BIC.
In a triangle ABC, ∠A = 70°, ∠B = 80° and D is the incenter of ΔABC, ∠ACB = 2x° and ∠BDC = y°. The values of x and y, respectively are:
চিত্রে-i. ∠ABC∠ACB ii. ∠ACB =∠BAC iii. ∠ACB + ∠BAC = ∠ABC নিচের কোনটি সঠিক?
I is the incentre of ΔABC, ∠ABC = 60° and ∠ACB = 50°, Then ∠BIC is
In the given figure, x is the incentre of Δ  ABC, ∠ ABC = 60° and ∠ ACB = 50°, BX and CX are angle bisectors of ∠ ABC and ∠ ACB respectively, then what is the value of ∠ BXC ?  
The sides AB and AC of a ∆ABC are produced up to points D and E. The bisectors of the exterior angles to formed. intersect each other at point I if ∠ACB is 660 and ∠ABC is 440, then what is the measure (in degrees) of ∠BIC?
I is the incentre of a triangle ABC. If ∠ACB = 55°, ∠ABC = 65° then the value of ∠BIC is
I is the incentre of ΔABC. If ∠ABC = 60°, ∠BCA = 80°, then the ∠BIC is
The perimeter of ΔABC and ΔDEF are 39.6 cm and 26.4 cm, respectively, and ΔABC ~ ΔDEF. What is the ratio of the areas of ΔABC and ΔDEF?
In ΔABC, ∠A = 90° and radius of the in-circle of the ΔABC is 3 cm and BC = 17 cm, then, what is the area (in sq. cm) of the ΔABC?