A box contains 10 electric bulbs from which 2 bulbs are defective . Two bulbs are chosen at random. What is the probability that one of them is defective?
A
3/10
B
16/45
C
25/68
D
8/33
Correct Answer: 16/45
Defective 2; Normal ৪ Probability that one of them is defective will be, = (8C1×2C2)/10C2 = (8×2)/45 = 16/45 (ans)