Related Questions

Determine the corrections or otherwise of the following Assertion and Reason : Assertion : For longitudinal static stability of an aircraft, slope of moment curve should be negative. Reason: Positive slope will result in more static stability than negative slope. Hence, slope should be positive always. and are true and is the correct reason for b) Both and are true but is not the correct reason for c) is true but is false d) is false but is true
The ratio of bed slope and the slope of energy line is 2, calculate the value of slope of energy line if the length of back water curve is 20000m. Given: E1=2m and E2=5m.
If dy/dx=3×10-4 m and the ratio of bed slope and slope of energy line is 0.7, calculate the value of slope of energy line if the uniform flow depth is 1.6m, critical depth is 1.2m.
On a P-V diagram of an ideal gas, suppose a reversible adiabatic line intersects a reversible isothermal line at point A. Then at a point A, the slope of the reversible adiabatic line $${\left( {\frac{{\partial {\text{P}}}}{{\partial {\text{V}}}}} \right)_{\text{S}}}$$  and the slope of the reversible isothermal line $${\left( {\frac{{\partial {\text{P}}}}{{\partial {\text{V}}}}} \right)_{\text{T}}}$$  are related as (where, $${\text{y}} = \frac{{{{\text{C}}_{\text{p}}}}}{{{{\text{C}}_{\text{v}}}}}$$  )
Find the slope of the operating line Here, the concentrations are represented in mole ratio. The value of (Y1-Y2)/(X1-X2) =2. Find the slope of the operating line.
Calculate the velocity of flow in a triangular channel having depth 7m and the side slope of the channel is 1H:4V if the bed slope of the channel is 1 in 1200 and the slope of the energy line is 0.00010. Given:( dy)/dx=7.55m.
If slope of a line is 2/3 then find the slope of line perpendicular to it.
When q=(Heat required to convert one mole of feed to saturated vapor)/(Molar heat of vaporization of feed) Statement 1: q<1 means the slope is a horizontal line. Statement 2: q<1 means the slope is a vertical line.
Given are the steps to draw a perpendicular to a line at a point within the line when the point is near the centre of a line. Arrange the steps. Let AB be the line and P be the point in it i. P as centre, take convenient radius R1 and draw arcs on the two sides of P on the line at C, D. ii. Join E and P iii. The line EP is perpendicular to AB iv. Then from C, D as centre, take R2 radius (greater than R1), draw arcs which cut at E.
Given are the steps to draw a perpendicular to a line from a point outside the line, when the point is near the centre of line. Arrange the steps. Let AB be the line and P be the point outside the line i. The line EP is perpendicular to AB ii. From P take convenient radius and draw arcs which cut AB at two places, say C, D. iii. Join E and P. iv. Now from centers C, D draw arc with radius (more than half of CD), which cut each other at E.