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What will be printed after compiling and running the following code?
main() { char *p; printf("%d %d",sizeof(*p), sizeof(p));}

What will be printed after compiling and running the following code?

main() { char *p; printf("%d %d",sizeof(*p), sizeof(p));}
Correct Answer 1 2

The sizeof() operator gives the number of bytes taken by its operand. p is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.

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