Two circles of equal radii touch externally at a point P . Form a point T on the target at P target TQ and TR are drawn to the circles with points of contact Q and R respectively. The relations of TQ and TR is

A T = TR
B TQ> TR
C TQ = TR
D TQ = 2 Tk.

Correct Answer: TQ = TR

TR, TP are two tangents drawn to a bigger circle from an external point T. we know that, length of tangents drawn from external point to circle are equal ∴TR = TP ___(i) Similarly TP, TQ are two tangent drawn to a smaller circle from an external point T. Again we have TP = TQ __(ii) From (i) & (ii), we have TR = TQ
Bissoy MCQ
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