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If points P and Y are just meeting at the point of contact between the dials , and if dial 1 spins at exactly three time the speed of dial 2, which of the following pairs of points will be the next pair to meet at the point of contact?

If points P and Y are just meeting at the point of contact between the dials , and if dial 1 spins at exactly three time the speed of dial 2, which of the following pairs of points will be the next pair to meet at the point of contact? Correct Answer P and Z

ডায়াল - 1 যেহেতু ডায়াল - 2 এর তিনগুণ গতিতে ঘুরবে তাইContact point - এ ডায়াল - 2 এর 2 আসতে আসতে ডায়াল - 1এর P আবার সেখানে চলে আসবে । অর্থাৎ contact point - এ জোড়টি হবে P, Z । যদি উভয় ডায়াল সমান গতিতে ঘুরতো সেক্ষেত্রে pair - টি হতো O, Z । সুতরাং options এর সঠিক উত্তর (d).

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Two circular dials of exactly the same size are mounted on a wall side by side in such a way that their perimeters touch at one point. Dial 1, which is on the left , spins clockwise around its center , and dial 2 , which is on the right spins counter clockwise around its center . (Assume that there is no friction at the point of contact between the dials.) Each dial is marked on its perimeter at three points that are at equale distances around the points arked ondial 1 are N, O, and P and the points marked on dial 2 are X, Y, and Z. If points O and Z are just meeting at the point of contact between the dials , and if dial 1 spins at the same speed as dial 2, what is the smallest number of revolutions of each dial that will bring O and Z together again?
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