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The disintegration energy is defined to be the difference in the rest energy between the initial and final states. Consider the following process: $${}_{94}^{240}{\text{Pu}} \to {}_{92}^{236}{\text{U}} + {}_2^4{\text{He}}$$
The emitted α-particle has a kinetic energy 5.17 MeV. The value of the disintegration energy is

The disintegration energy is defined to be the difference in the rest energy between the initial and final states. Consider the following process: $${}_{94}^{240}{\text{Pu}} \to {}_{92}^{236}{\text{U}} + {}_2^4{\text{He}}$$
The emitted α-particle has a kinetic energy 5.17 MeV. The value of the disintegration energy is Correct Answer 5.26 MeV

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