A particle of mass m is confined in an infinite potential well \[V\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {0,}&{{\text{if }}0 It is subjected to a perturbing potential $${V_P}\left( x \right) = {V_0}\sin \left( {\frac{{2\pi x}}{L}} \right)$$     within the well. Let E(1) and E(2) be the corrections to the ground state energy in the first and second order in V0.
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Which of the following is correct?

A particle of mass m is confined in an infinite potential well \[V\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {0,}&{{\text{if }}0 It is subjected to a perturbing potential $${V_P}\left( x \right) = {V_0}\sin \left( {\frac{{2\pi x}}{L}} \right)$$     within the well. Let E(1) and E(2) be the corrections to the ground state energy in the first and second order in V0.
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Which of the following is correct? Correct Answer E<sup>(1)</sup> = 0; E<sup>(2)</sup> depends on the sign of V<sub>0</sub>

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