A particle of mass m is confined in an infinite potential well \[V\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {0,}&{{\text{if }}0 It is subjected to a perturbing potential $${V_P}\left( x \right) = {V_0}\sin \left( {\frac{{2\pi x}}{L}} \right)$$ within the well. Let E(1) and E(2) be the corrections to the ground state energy in the first and second order in V0.

Which of the following is correct?
A particle of mass m is confined in an infinite potential well \[V\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {0,}&{{\text{if }}0 It is subjected to a perturbing potential $${V_P}\left( x \right) = {V_0}\sin \left( {\frac{{2\pi x}}{L}} \right)$$ within the well. Let E(1) and E(2) be the corrections to the ground state energy in the first and second order in V0.
Which of the following is correct? Correct Answer E<sup>(1)</sup> = 0; E<sup>(2)</sup> depends on the sign of V<sub>0</sub>
মোঃ আরিফুল ইসলাম
Feb 20, 2025









