The degree of the differential equation $$\frac{{{{\text{d}}^2}{\text{x}}}}{{{\text{d}}{{\text{t}}^2}}} + 2{{\text{x}}^3} = 0$$ is
The degree of the differential equation $$\frac{{{{\text{d}}^2}{\text{x}}}}{{{\text{d}}{{\text{t}}^2}}} + 2{{\text{x}}^3} = 0$$ is Correct Answer 1
মোঃ আরিফুল ইসলাম
Feb 20, 2025
