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A metal crystallizes into two cubic phases BCC and FCC. The ratio of densities of FCC and BCC is equal to 1.5. Calculate the difference between the unit cell lengths of the FCC and BCC crystals if the edge length of the FCC crystal is equal to 4.0 Å.
Atoms of element X form a BCC and atoms of element Y occupy 3/4th of the tetrahedral voids. What is the formula of the compound?
If N is the number of tetrahedral voids in a close-packed structure, then the number of octahedral voids is:
Ratio of tetrahedral to octahedral voids in FCC
An octahedral void is present at each edge of the FCC lattice. How much of each of these voids belong to each unit cell?
Column A lists the cell parts and Column B lists the functions of the cell part. Column A Column B i. Cell wall A. Control what happens ii. Cell membrane B. Supports the cell. iii. Cytoplasm C. Controls what passes in and out of the cell. iv. Nucleus D. Cell reactions happen in it. Which one of the following options is correct?
A compound is made up of three elements X, Y and Z. X atoms are present at each corner of the unit cell, Y atoms are present on each edge and Z atoms are present in the centre of each face. The formula of the compound is:
All the forms of matter except gases emit electromagnetic radiation continuously. The gases which electrically or thermally excited emit a certain wavelength only, then which of the following is/are true about the process (i) The spacing between the atoms in the other forms of matter is high than in gas (ii) The spacing between the atoms in gases is high than the other forms of matter (iii) The energy of the emitted radiation depends on the spacing between the atoms (iv) The wavelength of the emitted radiation depends on the spacing between the atoms 
A collection of N atoms is exposed to a strong resonant electromagnetic radiation with Ng atoms in the ground state and N atoms in the excited state, such that Ng + Ne = N. This collection of two-level atoms will have the following population distribution
An element of density 8.0 g/cm3 forms an FCC lattice with unit cell edge of 300 pm. Calculate the number of atoms present in 0.5kg of the element.