In an ionic crystal if the valancies of cation and anion are V_C and V_A and the coordination numbers of cation and anions are Nc and N_A respectively, then the necessary condition for obtaining a stable crystal structure is

$$\frac{{{V_C}}}{{{N_C}}} = \frac{{{V_A}}}{{{N_A}}}$$

VC.VA = NC.NA

$$\frac{{{V_C}}}{{{N_A}}} = \frac{{{V_A}}}{{{N_C}}}$$

$$\frac{{{V_C}}}{{{V_A}}} = \frac{{\surd {N_C}}}{{\surd {N_A}}}$$

In an ionic crystal if the valancies of cation and anion are V_C and V_A and the coordination numbers of cation and anions are Nc and N_A respectively, then the necessary condition for obtaining a stable crystal structure is Correct Answer $$\frac{{{V_C}}}{{{V_A}}} = \frac{{\surd {N_C}}}{{\surd {N_A}}}$$

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Feb 20, 2025

Metallurgical Engineering
Physics Of Metals In Metallurgy

In an ionic crystal if the valancies of cation and anion are VC and VA and the coordination numbers of cation and anions are Nc and NA respectively, then the necessary condition for obtaining a stable crystal structure is

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In an ionic crystal if the valancies of cation and anion are V_C and V_A and the coordination numbers of cation and anions are Nc and N_A respectively, then the necessary condition for obtaining a stable crystal structure is