FeO(s) + CO(g) = Fe(s) + CO2(g); K = 0.435 at 1173 K. At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173K?
FeO(s) + CO(g) = Fe(s) + CO2(g); K = 0.435 at 1173 K. At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173K? Correct Answer 3.3
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Feb 20, 2025