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A fan running at a speed of 280 rpm circulates 105 m3/s of air in a mine. If the power input to the motor for driving the fan is recorded to be 75 kW, with the combined efficiency of fan and motor at 70%. the fan pressure in Pa is

A fan running at a speed of 280 rpm circulates 105 m3/s of air in a mine. If the power input to the motor for driving the fan is recorded to be 75 kW, with the combined efficiency of fan and motor at 70%. the fan pressure in Pa is Correct Answer 500

Related Questions

A fan running at a speed of 280 rpm circulates 105 m3/s of air in a mine. If the power input to the motor for driving the fan is recorded to be 75 kW, with the combined efficiency of fan and motor at 70%. If the fan pressure is to be increased by 200 Pa by changing the fan speed. the fan speed in rpm will become
A mine ventilation system consists of two splits A and B with resistances of 0.8 Ns2m-8 and 3.2 Ns2m-8, respectively as shown in figure. Trunk airways have resistance of 0.2 Ns2m-8. The main mine fan is generating pressure of 500 Pa.
Mine Ventilation mcq question image
The flows in the two splits are equalized by placing a booster fan in split B. Assume that the fan pressure does not change after installation of the booster fan. The size of the booster fan in Pa is
A main fan of a mine circulates 40 m3/s of air at a pressure of 500 Pa. the mine has two splits of equal resistance. The trunk airways have a total resistance of 0.2 Ns2/m8. When a booster fan is installed in one split, the flow of air in the other splits stops. Assuming that the pressure remains unchanged, the new air quantity flowing through the mine in m3/s is
A mine fan produces 30 m3/s of air at 240 Pa pressure running at 1400 rpm. If the fan speed is increased to 2100 rpm, the pressure in Pa and the quantity in m3/s generated by the fan will be
Pressure characteristic of a mine fan is given by. P = -0.06Q2 + 400. where P is the pressure in Pa and Q is the quantity in m3/s. The resistance of the mine is 0.19 Ns2/m8. An identical fan is installed in the mine to operate in series with the existing fan. The new mine quantity in m3/s is
An exhaust fan attached to an evasee of 18 m2 cross-sectional area at the outlet circulates 150 m3/s of air at the pressure of 1000 Pa in a mine ventilation system. The ratio of the inlet to outlet area of the evasee is 1 : 4 and the density of air is 1.2 kg/m3. The quantity of air circulated in the mine in absence of evasee is 120 m3/s. The eva see efficiency in % is
A mine ventilation system consists of two splits A and B with resistances of 0.8 Ns2m-8 and 3.2 Ns2m-8, respectively as shown in figure. Trunk airways have resistance of 0.2 Ns2m-8. The main mine fan is generating pressure of 500 Pa.
Mine Ventilation mcq question image
The air quantities in m3/s circulated in the splits A and B respectively are
Shikha went to the market to purchase five fans. The cost of the first fan is 25% more than the second fan and price of third fan is 20% less than fourth fan and price of fifth fan is 16% more than price of fourth fan. Price of the fourth fan is 3/4th of the second fan’s price. If the average cost of the first three fans was Rs.35 more than of the last three fans. What is  the cost of the second costliest fan?
The figure shows PV (pressure-volume) diagram of a mine ventilated by both natural means and an exhaust fan. The total ventilation energy is represented by
Mine Ventilation mcq question image
The fan drift pressure readings and fan quantities are measured to be 500 Pa and 65 m3/s respectively at the time when NVP aids fan pressure. On reversal, the fan delivers a quantity of 50 m3/s while acting against NVP with fan drift pressure of 600 Pa. Assuming that the NVP remains constant in both cases the total resistance of the mine in Ns2/m8 will be