The length and breadth of a square of a are increased by 40% and 30% receptively. The area of the resulting rectangle exceeds the are of the square by?
A
62%
B
42%
C
82%
D
None of the above
Correct Answer: 82%
Let, length is = x so, area is = x2 40% increase in length = x + 2x/5 = 7x/5 30% increase in breadth = x + 3x/10 = 13x/10 Area = (7x/5)×( 13x/10) = 91×2/50 Increasing area = (91×2/50) - x2 = 41×2/50 Percentage = {(41×2/50) x2}×100 = (41/50)×100 = 82%