The length and breadth of a square of a are increased by 40% and 30% receptively. The area of the resulting rectangle exceeds the are of the square by?

A 62%
B 42%
C 82%
D None of the above

Correct Answer: 82%

Let, length is = x so, area is = x2 40% increase in length = x + 2x/5 = 7x/5 30% increase in breadth = x + 3x/10 = 13x/10 Area = (7x/5)×( 13x/10) = 91×2/50 Increasing area = (91×2/50) - x2 = 41×2/50 Percentage = {(41×2/50) x2}×100 = (41/50)×100 = 82%
Bissoy MCQ

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