In a shell and tube heat exchanger having triangular pitch, the shell side equivalent diameter is given by
A
$$\frac{{4\left( {0.86{{\text{p}}^2} - \pi {{\text{d}}^2}/4} \right)}}{{\pi {\text{d}}}}$$
B
$$\frac{{{{\text{p}}^2} - \pi {{\text{d}}^2}/4}}{{\pi {\text{d}}}}$$
C
$$\frac{{4\left( {0.86{{\text{p}}^2} - \pi {{\text{d}}^2}} \right)}}{{\pi {\text{d}}}}$$
D
$$\frac{{4{{\text{p}}^2} + \pi {{\text{d}}^2}/4}}{{\pi {\text{d}}}}$$
Correct Answer: $$\frac{{4\left( {0.86{{\text{p}}^2} - \pi {{\text{d}}^2}/4} \right)}}{{\pi {\text{d}}}}$$