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Simplify the value of $$\frac{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} \times {\text{0}}{\text{.3}} - {\text{3}} \times 0.9 \times {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}}}}{{{\text{0}}{\text{.9}} \times {\text{0}}{\text{.9 + 0}}{\text{.2}} \times {\text{0}}{\text{.2 + 0}}{\text{.3}} \times {\text{0}}{\text{.3}} - 0.9 \times {\text{0}}{\text{.2}} - {\text{0}}{\text{.2}} \times {\text{0}}{\text{.3}} - 0.3 \times 0.9}} = ?$$
$$\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}$$            is equal to = ?
In a swimming race, Purab swam faster than Sachin. Varun swam faster than Tanmay. Zaid swam faster than Tanmay but not as fast as Sachin. Sachin swam slower than Varun.Varun swam faster than only three. Who among the given friends came first in the race?
Usha runs faster than Kapil. Hanif runs faster than Usha. Varsha runs faster than Sameer but slower than Bijli. Which ofthe following will be definitely correct if Sameer runs faster than Hanif?
Consider the following statements regarding crack : 1. Crack is more likely to occur in the regions of discontinuity such as oil holes. 2. Crack is more likely to occur in the regions of irregularities in machining operations such as stamp mark. 3. Crack is more likely to occur in the internal cracks due to defects in materials like blow holes. Which of the above statements are correct ? 
Catalytic cracking process are more expensive to run than the thermal cracking process.
Fluid-bed catalytic cracking products contain high proportions of aromatic and iso-paraffin compounds than thermal cracking process.
Two boats go downstream from point X to Y. The faster boat covers the distance from X to Y, 1.5 times as fast as slower boat. It is known that for every hour slower boat lags behinds the faster boat by 8 km. however, if they go upstream, then the faster boat covers the distance from Y to X in half the time as the slower boat. Find the speed of the faster boat in still water?
$$\eqalign{ & {\text{The}}\,{\text{value}}\,{\text{of}} \cr & \frac{{0.1 \times 0.1 \times 0.1 + 0.02 \times 0.02 \times 0.02}}{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}\,\text{is}: \cr} $$
The value of $$\left( {\frac{{0.1 \times 0.1 \times 0.1 + 0.02 \times 0.02 \times 0.02}}{{0.2 \times 0.2 \times 0.2 + 0.04 \times 0.04 \times 0.04}}} \right)$$       is :