The inherent characteristic of an equal percentage valve relating flow rate 'q' with valve stem movement 'x' are described by the equation
A
$$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}}$$
B
$$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}} \times {\text{q}}$$
C
$$\frac{{{\text{dq}}}}{{{\text{dx}}}} = \frac{{\text{K}}}{{\text{q}}}$$
D
$$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}} \times {{\text{q}}^2}$$
Correct Answer: $$\frac{{{\text{dq}}}}{{{\text{dx}}}} = {\text{K}}$$
