If the modular ratio is ‘m’, steel ratio is ‘r’ and overall depth of a beam is ‘d’, the depth of the critical neutral axis of the beam, is

A $$\frac{{\text{m}}}{{{\text{m}} - {\text{r}}}} \times {\text{d}}$$
B $$\frac{{\text{m}}}{{{\text{m}} + {\text{r}}}} \times {\text{d}}$$
C $$\frac{{{\text{m}} + {\text{r}}}}{{\text{m}}} \times {\text{d}}$$
D $$\frac{{{\text{r}} - {\text{m}}}}{{\text{m}}} \times {\text{d}}$$

Correct Answer: $$\frac{{\text{m}}}{{{\text{m}} + {\text{r}}}} \times {\text{d}}$$

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