Related Questions

When a closely-coiled helical spring of mean diameter (D) is subjected to an axial load (W), the deflection of the spring ($$\delta $$) is given by (where d = Diameter of spring wire, n = No. of turns of the spring and C = Modulus of rigidity for the spring material)
A $$\frac{{{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
B $$\frac{{2{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
C $$\frac{{4{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
D $$\frac{{8{\text{W}}{{\text{D}}^3}{\text{n}}}}{{{\text{C}}{{\text{d}}^4}}}$$
A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is $$\tau $$. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be
A $$\frac{\tau }{2}$$
B $$\tau $$
C $$2\tau $$
D $$4\tau $$
The capacity of a spring to store energy is called the spring form co-efficient. Stiffness of a spring is measured by the
A Ability to absorb shock
B Capacity to store energy
C Ratio of the wire & coil diameters
D Load to produce unit deflection
Information: The daily average sale of apples in a fruit store is 70 kg. The price of apple per kg is Tk. 200. Due to a faulty weighing machine the store owner actually gives away 1005 grams instead of 1 kg to customers. The store operates . The store operator 300 days every year. Calculation: What is the daily loss of the seller in kg because of the faulty weighing machine?
A 0.50
B 0.25
C 0.35
D 0.45
Information: The daily average sale of apples in a fruit store is 70 kg. The price of apple per kg is Tk. 200. Due to a faulty weighing machine the store owner actually gives away 1005 grams instead of 1 kg to customers. The store operates . The store operator 300 days every year. Calculation: How many kg the seller gives away for free in a year?
A 85
B 105
C 115
D 95
Information: The daily average sale of apples in a fruit store is 70 kg. The price of apple per kg is Tk. 200. Due to a faulty weighing machine the store owner actually gives away 1005 grams instead of 1 kg to customers. The store operates . The store operator 300 days every year. Calculation: What is the sale of the fruit (in Tk.) in a day?
A 8500
B 10000
C 12000
D 14000
Information: The daily average sale of apples in a fruit store is 70 kg. The price of apple per kg is Tk. 200. Due to a faulty weighing machine the store owner actually gives away 1005 grams instead of 1 kg to customers. The store operates . The store operator 300 days every year. Calculation: What is the loss of the seller (in Tk.) in a day year because of the faulty machine?
A 21000
B 18000
C 105000
D 12500
Two closely coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is half that of spring 'B'. The ratio of deflections in spring 'A' to spring 'B' is
A $$\frac{1}{8}$$
B $$\frac{1}{4}$$
C $$\frac{1}{2}$$
D 2
When an open coiled helical compression spring is subjected to an axial compressive load, the maximum shear stress induced in the wire is (where D = Mean diameter of the spring coil, d = Diameter of the spring wire, K = Wahl's stress factor and W = Axial compressive load on the spring)
A $$\frac{{{\text{WD}}}}{{\pi {{\text{d}}^3}}} \times {\text{K}}$$
B $$\frac{{2{\text{WD}}}}{{\pi {{\text{d}}^3}}} \times {\text{K}}$$
C $$\frac{{4{\text{WD}}}}{{\pi {{\text{d}}^3}}} \times {\text{K}}$$
D $$\frac{{8{\text{WD}}}}{{\pi {{\text{d}}^3}}} \times {\text{K}}$$
Two closely-coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be __________ that of spring 'B'.
A One-sixteenth
B One-eighth
C One-fourth
D One-half

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