A thin spherical shell of internal diameter d is subjected to an internal pressure p. If $${\sigma _{\text{t}}}$$ is the tensile stress for the shell material, then thickness of shell is equal to

A $$\frac{{{\text{pd}}}}{{{\sigma _{\text{t}}}}}$$
B $$\frac{{{\text{pd}}}}{{2{\sigma _{\text{t}}}}}$$
C $$\frac{{{\text{pd}}}}{{3{\sigma _{\text{t}}}}}$$
D $$\frac{{{\text{pd}}}}{{4{\sigma _{\text{t}}}}}$$

Correct Answer: $$\frac{{{\text{pd}}}}{{4{\sigma _{\text{t}}}}}$$

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