A binary symmetric channel (BSC) has a transition probability of $$\frac{1}{8}.$$  If the binary transmit symbol X is such that $$P\left( {X = 0} \right) = \frac{9}{{10}},$$    then the probability of error for an optimum receiver will be

A binary symmetric channel (BSC) has a transition probability of $$\frac{1}{8}.$$  If the binary transmit symbol X is such that $$P\left( {X = 0} \right) = \frac{9}{{10}},$$    then the probability of error for an optimum receiver will be Correct Answer $$\frac{7}{{80}}$$

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