In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11?

In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11? Correct Answer $$\frac{5}{36}$$

In a simultaneous throw of two dice, we have n (S) = (6 × 6) = 36
Let E = event of getting a total of 10 or 11
=
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{5}{{36}}$$

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