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A number consists of two digits such that the digit in the ten's place is less by 2 than the digit in the unit's place. Three times the number added to $$\frac{6}{7}$$ times the number obtained by reversing the digits equals 108. The sum of the digits in the number is :

A number consists of two digits such that the digit in the ten's place is less by 2 than the digit in the unit's place. Three times the number added to $$\frac{6}{7}$$ times the number obtained by reversing the digits equals 108. The sum of the digits in the number is : Correct Answer 6

Let the unit's digit be x
Then, ten's digit = (x - 2)
$$\therefore 3\left + \frac{6}{7}$$     $$\left$$   $$ = 108$$
⇔ 231x - 420 + 66x - 12 = 756
⇔ 297x = 1188
⇔ x = 4
Hence, sum of the digits :
= x + (x - 2)
= 2x - 2
= 6

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