A monkey climbs a 60 m high pole. In first minute he climbs 6 m and slips down 3 m in the next minute. How much time is required by it to reach the top?

A monkey climbs a 60 m high pole. In first minute he climbs 6 m and slips down 3 m in the next minute. How much time is required by it to reach the top? Correct Answer 37 minutes

Monkey climbs 6 m in 1st minute and slips down 3 m in next minutei.e. Monkey climbs 3 meter in 2 minute then he climbs in one minute,= $$\frac{3}{2}$$ m.But in the last minute he climbs 6 m as he gets on the top so there is no slip.Time required = $$2 \times \frac{{54}}{3} + \frac{6}{6}$$   = 37 minutes.
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