The value of the integral $$\oint\limits_C {\frac{{{e^z}\sin z}}{{{z^2}}}} dz,$$ where the contour C is the unit circle: |z - 2| = 1, is
The value of the integral $$\oint\limits_C {\frac{{{e^z}\sin z}}{{{z^2}}}} dz,$$ where the contour C is the unit circle: |z - 2| = 1, is Correct Answer zero
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Feb 20, 2025
