The centre of gravity of the trapezium as shown in below figure from the side is at a distance of

The centre of gravity of the trapezium as shown in below figure from the side is at a distance of
Correct Answer $$\frac{{\text{h}}}{3} \times \frac{{{\text{b}} + {\text{2a}}}}{{{\text{b}} + {\text{a}}}}$$
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Feb 20, 2025









