In case of S.H.M. the period of oscillation (T), is given by
A
$${\text{T}} = \frac{{2\omega }}{{{\pi ^2}}}$$
B
$${\text{T}} = \frac{{2\pi }}{\omega }$$
C
$${\text{T}} = \frac{2}{\omega }$$
D
$${\text{T}} = \frac{\pi }{{2\omega }}$$
Correct Answer: $${\text{T}} = \frac{{2\pi }}{\omega }$$
