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PQ is the chord of a circle whose centre is O. ROS is a line segment originating from a point R on the circle that intersect PQ produced at point S such that QS = OR. If ∠QSR = 30°, then what is the value (in degrees)of POR?

PQ is the chord of a circle whose centre is O. ROS is a line segment originating from a point R on the circle that intersect PQ produced at point S such that QS = OR. If ∠QSR = 30°, then what is the value (in degrees)of POR? Correct Answer 90

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PQ is the chord of a circle whose centre is O. ROS is a line segment originating from a point R on the circle that intersect PQ produced at point S such that QS = OR. If ∠QSR = 30°, then what is the value (in degrees)of POR?
PQ is the chord of a circle whose centre is O. ROS is a line segment originating from a point R on the circle that intersect PQ produced at point S such that QS = OR. If ∠QSR = 30°, then what is the value (in degrees) of POR?
PQ is the chord of a circle whose centre is O. ROS is a line segment originating from a point R on the circle that intersect PQ produced at point S suchthat QS = OR. If ∠QSR = 30°, then what is the value (in degrees)of POR?
If the code for “Sin por true” is “tur gfr try”, “True tum gir” is “lyn tur sur” and “Por tum sin” is coded as “sur try gfr”. Then, what is the code for “Sin por”?
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A circle whose radius is of 10 cm is having a chord inside it which is RS at a distance of 6 cm from it. It is having another chord PQ inside it which intersects chord PQ at T such that TS = 1/6 of RT. Find the value of chord PQ?
Segment CD is shorter than Segment MN, Segment MN is shorter than Segment TR, Segment AB is shorter than Segment CD and Segment MN is shorter than Segment PQ. Which segment is the shortest?
Consider a circle with centre at C. Let OP, OQ denote respectively the tangents to the circle drawn from a point O outside the circle. Let R be a point on OP and S be a point on OQ such that OR × SQ = OS × RP. Which of the following statement(s) is/are correct? (1) If X is the circle with centre at O and radius OR, and Y is the circle with centre at O and radius OS, then X = Y (2) ∠POC + ∠QCO = 90° Select the correct answer using the code given below.
Given are the steps to draw a perpendicular to a line at a point within the line when the point is near the centre of line. Arrange the steps. Let AB be the line and P be the point in it i. Join F and P which is perpendicular to AB. ii. Now C as centre take the same radius and cut the arc at D and again D as centre with same radius cut the arc further at E. iii. With centre as P take any radius and draw an arc (more than a semicircle) cuts AB at C. iv. Now D, E as centre take radius (more than half of DE) draw arcs which cut at F.