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Consider 5 independent Bernoullis trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ?

Consider 5 independent Bernoullis trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ? Correct Answer

Probability of atleast one failure= 1 - no failure > 31/32= 1 - P5 > 31/32=  P5<1/32= p < 1/2Also p > 0Hence p lies in [0,1/2].

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