The sum of ages of 2 brothers is 45 years. If their ages are in a ratio 4:5, find their ages after 10 years.
The sum of ages of 2 brothers is 45 years. If their ages are in a ratio 4:5, find their ages after 10 years. Correct Answer 30, 35 years
Let their ages be x and y, respectively. X:y = 4:5 x / 4 = y / 5 5x = 4y X + y = 45 4(x + y) = 45 * 4 (multiplying both sides by 4) 4x + 4y = 180 4x + 5x = 180 9x = 180, x = 20 Y = 45 – x = 45 – 20 = 25 X = 20 years, y = 25 years After 10 years: X = 20 + 10 = 30 years Y = 35 years