What is the value of k, if HCF of x2-x-2 and 2x2-kx-4 is (x-k)?
What is the value of k, if HCF of x2-x-2 and 2x2-kx-4 is (x-k)? Correct Answer 2
x-k is HCF of x2-x-2 and x2+kx-8. 2k2-k2-4 = 0 So, k = ±2. x2-x-2 = (x-2)(x+1). Therefore k = 2, so that the HCF is x-2.
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Feb 20, 2025