Find the HCF of x2-y2, x6-y6 and x10+y10.
Find the HCF of x2-y2, x6-y6 and x10+y10. Correct Answer 1
x2-y2 = (x+y(x-y) and x6-y6 = (x+y)(x-y)(x4+y4+x2y2). We know that x+y and x-y are not the factors of x10+y10. Therefore, HCF is 1.
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Feb 20, 2025