Find the HCF of 16(x5+x4-6x3) and 40(x4+4x3+3x2).
Find the HCF of 16(x5+x4-6x3) and 40(x4+4x3+3x2). Correct Answer 8x2(x+3)
Let p(x) = 16(x5+x4-6x3) = 16x3(x-2)(x+3) and q(x) = 40(x4+4x3+3x2) = 40x2(x+1)(x+3). The common factors are 8x2(x+3). Therefore, HCF is 8x2(x+3).
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Feb 20, 2025