The equal sides of an isosceles triangle is 8cm and the other side is 10 cm. What will be the area of this triangle in sq. cm?

The equal sides of an isosceles triangle is 8cm and the other side is 10 cm. What will be the area of this triangle in sq. cm? Correct Answer 31.22

Perimeter = 8 + 8 + 10 = 26 cm Semi – perimeter = 26 / 2 = 13 cm Area of triangle = √s(s – a) (s – b) (s – c) ➩ √13 (13 – 8) (13 – 8) (13 – 10) ➩ √13 (5) (5) (3) ➩ √975 ➩ 31.22 cm2

Related Questions

The given question consists of three statements numbered I, II and III. You have to decide whether the data provided in the statements are sufficient to answer the question. Read all the statements and answer the question. What is the area of an isosceles triangle? I. Perimeter of isosceles triangle is 28 m. II. Base of the triangle is 18 m. III. Height of the triangle is 13 m.