From 5 vowels and 4 consonants, how many words can be formed using 3 vowels and 2 consonants?

From 5 vowels and 4 consonants, how many words can be formed using 3 vowels and 2 consonants? Correct Answer 7200

Given that, 3 out of 5 vowels and 2 out of 4 consonants. So, (nCr * nCr). Where nCr = n! / r!(n – r)!. (5C3 * 4C2) = (5! / 3!(5 – 3)! * 4! / 2! (4 – 2)!) = (5 * 4 * 3!) / (3! * 2!) * (4 * 3 * 2!) / (2! * 2!)). (10 * 6) = 60. Number of words, each having 3 vowels and 2 consonants = 60. Each word contains 5 letters. Number of ways of arranging 6 letters among themselves = 5! = 120. Required number of ways = (60 * 120) = 7200.