If the sum of n terms of an AP is (3n2 + n) and Tm = 166, then what is the value of m?
If the sum of n terms of an AP is (3n2 + n) and Tm = 166, then what is the value of m? Correct Answer 28
Given that Sn = (3n2 + n) and Tm = 166 We know that, Tm = Sm – Sm-1 166 = 3m2 + m – 3(m-1)2 – (m-1) 166 = 6m – 2 Hence, m = 28
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Feb 20, 2025