The radius of a roller is 42 cm and its length is 110 cm. It takes 200 complete revolutions to move once over to level a small playground. What is the area (in sq. m) of the playground?

The radius of a roller is 42 cm and its length is 110 cm. It takes 200 complete revolutions to move once over to level a small playground. What is the area (in sq. m) of the playground? Correct Answer 580.8

Given, r = 42 cm, h = 110 cm, rev. = 200 Area of playground = rev * curved surface area of roller = rev * 2πrh = 200 * 2 * (22 / 7) * 42 * 110 cm2 = 200 * 2 * 22 * 6 * 110 = 5808000 cm2 = 580.8 m2
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