Find the energy in the flywheel having maximum fluctuation of energy 20 kN – m and coefficient of fluctuation of speed 0.20.

Which of the following is the expression of the maximum fluctuation of energy in a flywheel where I = mass moment of inertia of the flywheel, Cs = coefficient of fluctuation of speed, ω = mean angular speed of ω1 and ω2, and E = mean kinetic energy of the flywheel?

A

I*ω*(ω1+ω2)

B

I*ω*Cs

C

2*E2*Cs

D

I*ω2*Cs

Find the rim mean radius of the flywheel, given mass of the flywheel – 200 kg, angular velocity – 40 rad/s, coefficient of fluctuation of speed – 0.5 and maximum fluctuation of energy – 10 kN – m.

A

0.25 m

B

0.30 m

C

0.50 m

D

0.45 m

For a certain engine having an average speed of 1200 rpm, a flywheel approximated as a solid disc, is required for keeping the fluctuation of speed within 2% about the average speed. The fluctuation of kinetic energy per cycle is found to be 2 kJ. What is the least possible mass of the flywheel if its diameter is not to exceed 1 m ?

A

40 kg

B

51 kg

C

62 kg

D

73 kg

Find the mass of the flywheel having a radius of gyration 1.5 m, angular velocity 10 rad/s, coefficient of fluctuation of speed 0.10 and maximum fluctuation of energy 15 kN – m.

A

650 kg

B

666 kg

C

645 kg

D

630 kg

Torque vs. theta graph of a flywheel is shown. Coefficient of fluctuation of speed is 0.2 and the mean angular velocity of the machine is 25 rad/s. Thickness of flywheel is 20mm and density of steel used is 7700kg/mᵌ. Calculate the outer radius of the flywheel.

A

402mm

B

202mm

C

540mm

D

468mm

What is the distance covered by boat N upstream in 5 hours? Which of the following option is sufficient alone to find the answer? A) Boat M is travelling downstream with 20% more downstream speed of boat N. Speed of boat M in still water is 10% more than the speed of boat N in still water. B) Boat M and Boat N are travelling downstream with speed 33 km/hr and 40 km/hr respectively and speed of boat M is still water is 2 times the speed of stream. C) Speed of boat M in still water is 6 km/hr less then speed of boat N in still water and speed of stream is 10 km/hr. D) Speed of stream is ½ times the speed of boat N in still water and downstream speed of boat M is 44 km/hr. E) Speed of stream is 10 km/hr and ratio of upstream speed of boat M and boat N is 3 : 2 respectively.

A

Only A and B

B

Only B and C

C

Only B

D

All A, B, C and D

E

None of A, B, C and D

A flywheel is fitted to the crankshaft of an engine having W as the amount of indicated work per revolution and permissible limits of coefficient of fluctuation of energy and speed as CE and CS respectively. The kinetic energy of the flywheel is given by

A

2WCE/CS

B

WCE/2CS

C

WCE/CS

D

WCS/2CE

A flywheel is fitted to the crankshaft of an engine having W as the amount of indicated work per revolution and permissible limits of coefficient of fluctuation of energy and speed as C_E and C_S respectively. The kinetic energy of the flywheel is given by

A

$$\frac{{2{\text{W}}{{\text{C}}_{\text{E}}}}}{{{{\text{C}}_{\text{S}}}}}$$

B

$$\frac{{{\text{W}}{{\text{C}}_{\text{E}}}}}{{{\text{2}}{{\text{C}}_{\text{S}}}}}$$

C

$$\frac{{{\text{W}}{{\text{C}}_{\text{E}}}}}{{{{\text{C}}_{\text{S}}}}}$$

D

$$\frac{{{\text{W}}{{\text{C}}_{\text{S}}}}}{{{\text{2}}{{\text{C}}_{\text{E}}}}}$$

If E = Mean kinetic energy of the flywheel, CS = Coefficient of fluctuation of speed and Δ E = Maximum fluctuation of energy, then

A

ΔE = E / CS

B

ΔE = E2 × CS

C

ΔE = E × CS

D

ΔE = 2 E × CS

Given that maximum fluctuation of energy is 2000 N-m/s and coefficient of fluctuation of speed is 0.02. What is the mean kinetic energy of flywheel?

A

50 kN-m/s

B

40 kN-m/s

C

30 kN-m/s

D

20 kN-m/s

Find the energy in the flywheel having maximum fluctuation of energy 20 kN – m and coefficient of fluctuation of speed 0.20.

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