A four-cylinder tractor engine develops 50 KW at 3000 engines when tested on a prony dynamometer on brake arm length of 96 cm. What is the torque?

A four-cylinder tractor engine develops 50 KW at 3000 engines when tested on a prony dynamometer on brake arm length of 96 cm. What is the torque? Correct Answer 159.15 Nm

P = 2πNT/ 60000 T = 50*60000/ 2π*3000 T = 3000000/2*3.14*3000 T = 3000000/18840 T = 159.15 Nm.

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The brake power (B.P.) of the engine is given by (where W = Brake load or dead load in newtons, $$l$$ = Length of arm in meters, N = Speed of engine in r.p.m., S = Spring balance reading in newtons, D = Diameter of brake drum in meters and d = Diameter of rope in meters)
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