Bissoy.com
Doctors Medicines MCQs Q&A

A steel sheet of thickness 25 mm is sheared with a knife, and the fracture length is 50 mm. Find the shear force required, if the tensile strength of steel is 250 MPa?

A steel sheet of thickness 25 mm is sheared with a knife, and the fracture length is 50 mm. Find the shear force required, if the tensile strength of steel is 250 MPa? Correct Answer 218 kN

The shear force needed to cause the fracture will be: -> Pmax=0.7σuhL -> 0.7*250*106*25*50*10-6 -> 218750 N = 218.7 kN.

Related Questions

The maximum shear force required to cause the fracture on any metal surface is empirically defined as _____________ (Where σu – ultimate tensile strength of the metal, h-sheet thickness, L- total length of the sheared edge)
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum shear stress will be
For a given component, the alternating stress is equal to 250 MPa, Mean stress is 100 MPa, and the ultimate tensile strength is 500 MPa. Find the yield strength of the material according to Goodman’s approach?
For a given component, the alternating stress is equal to 250 MPa, Mean stress is 100 MPa, and the ultimate tensile strength is 500 MPa. Find the yield strength of the material according to the Gerber’s approach?
A body starts yielding when it is subjected to stress state with principal stresses of 250 MPa, 50 MPa and - 50 MPa. What is the yield strength of the material. in MPa, if Tresca yield criterion is obeyed?
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The minimum normal stress will be
Calculate ultimate moment and shear of effective span is 30m, live load is 9kn/m, dead load excluding self weight is 2kn/m, load factors for dead load is 1.4 for live load is 1.6 cube strength of concrete fcu is 50n/mm2 cube strength at transfer is fci is 35n/mm2, tensile strength of concrete Ec is 34kn/mm2 loss ratio ɳ is 0.85 and 8mm diameter high tensile strength fpu is 1500n/mm2 are available for use and the modulus of elasticity of high tensile wires is 200kn/mm2?
A brittle material is mechanically tested in medium P in which it has surface energy γs = 0.9 J m-2. This material has a fracture strength of 300 MPa for a given flaw size. The same solid containing the same flaws is then tested in medium Q in which γs = 0.1 J m-2. The fracture strength (in MPa) in medium Q based on Griffith's theory is
A material has tensile strength 210 MPa, yield strength 117 MPa and fracture strain 0.45. What will be approximate value of toughness?