The stress intensity for a plate is given as K=σ√(π

The stress intensity for a plate is given as K=σ√(π Correct Answer 145 MPa

The stress intensity factor is given as: K=σ√(πa)tan (πta) So K= 50 MPa m-1/2, a= 5*10-3 m, t=1*10-2 m Substitute the values in the equatio50= σ √(3.14*5*10-3) tan(3.14*1*10-2*5*10-3) 50=σ*2.74*10-6*0.125 σ=147.058*106 σ=147.058 MPa So the allowable stress from the options will be equal to 145 MPa.
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