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What is the equilibrium spacing between the edge dislocation along a low angle grain boundary of 1.5-degree misorientation? (Given that the burger’s vector of dislocation is equal to 3 A°).

What is the equilibrium spacing between the edge dislocation along a low angle grain boundary of 1.5-degree misorientation? (Given that the burger’s vector of dislocation is equal to 3 A°). Correct Answer 115 A°

The misorientation, along with the grain boundary, is given in terms of θ: -> θ=b/D -> where D is equilibrium spacing So, (1.5*3.14)/180= 3*10-10/D -> D= 115.38*10-10 -> 115 A°.

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