The yield strength of a material is 200MPa when the grain size is 80 micron. If the frictional stress is 80MPa, find the strength when the grain diameter is 160 micron?
The yield strength of a material is 200MPa when the grain size is 80 micron. If the frictional stress is 80MPa, find the strength when the grain diameter is 160 micron? Correct Answer 180 MPa
According to the hall-patch relationship: σo=σi+kD-1/2 -> 200=80+k(80)-1/2 -> k=1252 So at D=160 σo=80+1252(160)-1/2 σo=178.9 MPa.
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Feb 20, 2025