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A tensile specimen of 6 mm diameter and gauge length 25 mm reached a maximum load of 45 kN and fractured at 35 kN. The maximum diameter at fracture is 5mm. Determine the engineering stress at maximum load (Ultimate tensile strength).

A tensile specimen of 6 mm diameter and gauge length 25 mm reached a maximum load of 45 kN and fractured at 35 kN. The maximum diameter at fracture is 5mm. Determine the engineering stress at maximum load (Ultimate tensile strength). Correct Answer 398 MPa

Engineering stress at maximum load = Pmax/Amax => Amax = π (diameter max.)2 => 45000/ π (6)2 *10-6 => 398 MPa.

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