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A uniform cylinder of length L is elongated to twice of its original length. Calculate true strain and engineering strain for the cylinder in percentage?

A uniform cylinder of length L is elongated to twice of its original length. Calculate true strain and engineering strain for the cylinder in percentage? Correct Answer Engineering strain=100%, True strain=69.31%

Initial length of cylinder=L; Final Length of cylinder=2L Engineering strain = (2L-L)/L= L/L=1 So, in the percent 100% True strain = ln(2L/L) = ln(2) = 0.6931 In percentage, it is 69.31%.

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